![]() Similarly, we can calculate the area of the windows.Īrea of one window = (1.5 x 1) m 2 = 1.5 m 2Ĭ) Now, let us calculate the area of the four walls. Findĭ) Cost of whitewashing the walls at the rate of £50 per square metre if the walls are 3.5 m high.Ī) Let us first understand what information has been provided in the question. It has one door of length 2 m and breadth 1.5 m and two windows each of length 1.5 m and breadth 1 m. Hence, the cost of cementing the floor of the gallery = £600 Example 7Ī room is 7 m long and 5.5 m broad. Rate of cementing the floor of the gallery = £20 per m 2Ĭost of cementing the floor of the gallery = £(20 x 30) = £600 Let ABCD represent the floor of the room and the shaded region represent the floor of the 1.25 m wide gallery.Īrea of the gallery = Area of the rectangle PQRS – Area of the rectangle ABCDī) Now that we have calculated the area of the gallery, we need to find out the cost of cementing of the gallery. Findī) The cost of cementing the floor of the gallery at the rate of £20 per m 2Ī) Let us first mark and understand the given information through a diagrammatic representation. Therefore, the length of the rectangle having area = 90cm 2 and breadth = 6 cm is 15 cm Example 6Ī gallery 1.25 m wide is constructed all along the outside of a room 5.5 m long and 4 m wide. We are given that area = 90cm 2 and breadth = 10 cm Hence, area of the path = 400 m 2 Example 5įind the length of a rectangle, if its area = 90cm 2 and breadth = 6 cm Let ABCD be the rectangular path and the shaded region represents the 2.5 m wide path to be constructed outside the park.Īrea of rectangle PQRS = (50 x 35) m 2 = 1750 m 2Īrea of rectangle ABCD = (45 x 30) m 2 = 1350 m 2Īrea of the path = Area of rectangle PQRS – Area of rectangle ABCD A path 2.5 m wide is constructed outside the park. Example 4Ī rectangular path is 45 m long and 30 m wide. The total cost of gravelling the path would be £ (544 x 5) = £2720. Since the total area to be gravelled is 544 m 2, therefore, We have been given that the cost of gravelling the path is £5 per square metre. Now, let us cost for gravelling the path. Total area of the path = Area of the path ABDC + Area of the path PQSR – Area of the path EFHG Hence we need to subtract this area once from our result to avoid counting it twice.Īrea of the path EFHG = (4 x 4) m 2 = 16 m 2 Since the grassy plot is a rectangle and we know that area of a rectangle having length ‘ l’ and breadth ‘b’ is given by l x b, therefore,Īrea of the path ABDC =(80 x 4) m 2 = 320 m 2Īgain, let us now find out the area of the path PQSR which can be calculated in the same manner as done above.Īrea of the path PQSR = (60 x 4) m 2 = 240 m 2īut, with the help of our figure, we can clearly see that the area of EFHG is common to both the areas that we have calculated just now. We have to find the total area used path.įirst, we will calculate the area of the path ABDC. Let the ABDC and PQSR be the rectangular paths that are to be constructed at right angles through the centre of the field, such that each path is parallel to one of the sides of the rectangles. Therefore, we will construct the rectangle and plot the details we have been given in the question. Also, find the cost of gravelling them at £ 5 per square metre.Īn important strategy for solving such questions is to first visualise them. Two cross paths each 4 m wide are constructed at right angles through the centre of the field, such that each path is parallel to one of the sides of the rectangles. Hence, Area of the rectangle = (0.36 x 0.29) m 2 = 0.1044 m 2 Example 3Ī grassy plot is 80 m 圆0 m. Hence, Area of the rectangle = (4.5 x 1.6) m 2 = 7.20 m 2 Example 2įind the area, in square metres, of a rectangle whoseī) length = 3 dm 6 cm, breadth = 2 dm 9 cm Since 2400 tiles completely cover the wall, therefore, Let the height of the wall be “h” metres. Therefore, area of 2400 tiles = 2400 x 500 cm 2 ![]() Length = Area / Breadth, Breadth = Area / Lengthįind the height of the wall whose length is 4m and which can be covered by 2400 tiles of size 25 cm by 20 cm.Īrea of tiles = (25 x 20) cm 2 = 500 cm 2 Since, Area of a rectangle = Length x Breadth, But, if only the length or breadth and area are given, is it possible to know the breadth of the rectangle? Let us find out. We now know how to calculate the area if we have the length and the breadth of a rectangle. The area of this rectangle is given by 8 7 7 = 56 cm 2.Īrea of a rectangle = length x breadth How to calculate the length and breadth of a rectangle using its area?
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